(x+5)^2/3=125

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Solution for (x+5)^2/3=125 equation: 


x in (-oo:+oo)

((x+5)^2)/3 = 125 // - 125

((x+5)^2)/3-125 = 0

((x+5)^2)/3+(-125*3)/3 = 0

(x+5)^2-125*3 = 0

x^2+10*x-350 = 0

x^2+10*x-350 = 0

x^2+10*x-350 = 0

DELTA = 10^2-(-350*1*4)

DELTA = 1500

DELTA > 0

x = (1500^(1/2)-10)/(1*2) or x = (-1500^(1/2)-10)/(1*2)

x = (10*15^(1/2)-10)/2 or x = (-10*15^(1/2)-10)/2

(x-((-10*15^(1/2)-10)/2))*(x-((10*15^(1/2)-10)/2)) = 0

((x-((-10*15^(1/2)-10)/2))*(x-((10*15^(1/2)-10)/2)))/3 = 0

((x-((-10*15^(1/2)-10)/2))*(x-((10*15^(1/2)-10)/2)))/3 = 0 // * 3

(x-((-10*15^(1/2)-10)/2))*(x-((10*15^(1/2)-10)/2)) = 0

( x-((-10*15^(1/2)-10)/2) )

x-((-10*15^(1/2)-10)/2) = 0 // + (-10*15^(1/2)-10)/2

x = (-10*15^(1/2)-10)/2

( x-((10*15^(1/2)-10)/2) )

x-((10*15^(1/2)-10)/2) = 0 // + (10*15^(1/2)-10)/2

x = (10*15^(1/2)-10)/2

x in { (-10*15^(1/2)-10)/2, (10*15^(1/2)-10)/2 }

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